Finite nontrivial LU moduli of AME states
- Field
- Topics
Problem
Do there exist integers \(N,d\geq 2\) for which the absolutely maximally entangled states of \(N\) qudits of local dimension \(d\) form finitely many, but more than one, local-unitary equivalence classes? A normalized vector \(|\psi\rangle\in(\mathbb{C}^{d})^{\otimes N}\) is an \(\operatorname{AME}(N,d)\) state when every subsystem of at most half the parties is maximally mixed:
For normalized states satisfying Eq. (1), define local-unitary equivalence by
If \(\mathcal{A}_{N,d}\) denotes the set specified by Eq. (1), determine whether the quotient under Eq. (2) can satisfy
Source
Rajchel-Mieldzioć et al. explicitly ask whether an AME family can have a finite number of local-unitary equivalence classes greater than one [RBR+26].
Progress
For four parties, all \(\operatorname{AME}(4,3)\) states lie in one LU class, whereas \(\operatorname{AME}(4,d)\) has infinitely many LU classes for every \(d\geq 4\) [RRKL23]. The latter theorem includes infinitely many inequivalent \(\operatorname{AME}(4,6)\) states, so neither side of this classification realizes Eq. (3).
Tan completely classifies five-qubit AME states: every such state is LU equivalent to a point of the unique \(((5,2,3))\) code \(\mathcal C\), and two points of \(\mathcal C\) are equivalent exactly when related by its finite binary-tetrahedral transversal group [Tan26]. Because the projective state space of the two-dimensional code is a continuum while this group is finite, \(\lvert\mathfrak{M}_{5,2}\rvert\) is infinite, not finite and nontrivial.
The 2026 AME review records the known one-class and infinite-class regimes and explicitly leaves Eq. (3) as open problem T5 [RBR+26].
Comment
The remaining task is either to exhibit an AME parameter pair whose full LU quotient is a discrete non-singleton set, or to prove that every nonempty \(\mathfrak{M}_{N,d}\) is a singleton or infinite. Classifying only a selected construction family would not determine the full quotient in Eq. (3).