Delayed-onset additivity violation for minimum output Rényi entropy
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Problem
Does there exist a finite-dimensional quantum channel whose minimum output Rényi entropy is additive for every tensor power below some order and first becomes strictly subadditive at that order? Let \(\Phi:\mathcal L(A)\to\mathcal L(B)\) be completely positive and trace preserving. For \(p>0\), define the Rényi entropy and the corresponding minimum output entropy by
With the quantities in Eq. (1), determine whether there are \(p>0\), an integer \(m\geq3\), and a channel \(\Phi\) such that
The restriction \(m\geq3\) in Eq. (2) makes the lower-power requirement nontrivial: the equality at \(n=1\) is automatic, whereas equality at \(n=2\) is required.
Source
Ruskai explicitly asks whether additivity can hold for all tensor powers below an integer \(m\) and fail at the \(m\)th power [Rus07]. Equation (2) uses the intended delayed-onset formulation \(m\geq3\), excluding the tautological one-copy-only condition obtained when \(m=2\).
Progress
Derksen and Lovitz construct explicit finite-dimensional self-channel violations \(S_{p,\min}(\Phi^{\otimes2})<2S_{p,\min}(\Phi)\) for every \(p>1\). These examples resolve the literal \(m=2\) reading, but fail the required two-copy equality in Eq. (2) for every \(m\geq3\) [DL26].
Hastings disproved minimum-output von Neumann entropy additivity at \(p=1\) using finite-dimensional random channels. The violation is already witnessed at a two-channel tensor product and therefore does not provide a channel that remains additive through every lower nontrivial power in Eq. (2) [Has09].
Comment
No channel is known to satisfy Eq. (2), and no general theorem is known that promotes two-copy additivity to additivity of all self-tensor powers. The unresolved issue is therefore the existence or impossibility of a genuinely delayed first violation at some \(m\geq3\).